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jarptica [38.1K]
3 years ago
14

5(x+4)+16 Match each of the following with Equivalent Expression listed on the right

Mathematics
1 answer:
son4ous [18]3 years ago
6 0
5(x+4)+16
5x+20+16
And then the solution is 5x+36
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Anyone know this? Ill give brainliest if right pls help ^^
Varvara68 [4.7K]

Answer:

Female=14 male=6

Step-by-step explanation:

Oof this toke long I understand it now, for yesterday you gotta do  6+6+6+6+6=30 this is the male and so you add 14 to 30=44, now comes the important part of solving this problem. For today you gotta add 4 men and 4 women so you do 6+6+6+6=24 now 14+14+14+14=56 and if you add 56+24=80 .

4 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIST PLEASE
ivolga24 [154]

Answer: D: 4.5

Step-by-step explanation:

So the Equation I used for this would be

6(2x+3) = 3(6x-3)

In Which the left is the Hexagon (The 6 is for the 6 Sides) and the right of the equation is the triangle (given the 3 for the 3 sides. In order to solve, we need to solve for x. Distribute the equation and your left with

12x+18=18x-9

-12x            +9

27=6x

Divide to get X by itself

and your left with

4.5 = x

Hope it helped.

3 0
3 years ago
A garden hose fills a 2-gallon bucket in 5 seconds.
natulia [17]
The filling rate is 2/5=0.4 gallons per second. So the appropriate equation is A.
5 0
3 years ago
Read 2 more answers
The graph shows y = cot(x). Which of the following are true of its inverse? Check all that apply.
Mama L [17]

Answer:

Zeroes: None

Domain: All real numbers

Maximum: None

Step-by-step explanation:

5 0
3 years ago
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
3 years ago
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