The answer is B
you have to find the cubic roots of 27 and 729 to find the side lengths of the cubes. The first one has a side length is 3, and the second one has a side length of 9 which s 3x larger.
pls make me brainliest ! ;-)
<span>5(-4) + 2y = -20
-20 + 2y = -20
2y = -20 + 20
2y = 0
y = 0</span>
Answer:
The length of the third side of given triangle lies between 6.5 and 19.9.
Step-by-step explanation:
The law of cosine is as follows
---------------1
⇒ a and b are the given sides of the triangle and c is the third side, and
is the angle between a and b .
In equation 1 , the maximum and minimum values of
are 1 and -1.
so the value of c lies in between
⇒
and
= ![|a-b| and |a+b|](https://tex.z-dn.net/?f=%7Ca-b%7C%20and%20%7Ca%2Bb%7C)
Given a=13.2 and b=6.7 so the the side lies in between |13.2-6.7| and |13.2+6.7|
so the third side lies between 6.5 and 19.9
Answer:
RM = 12 cm
Step-by-step explanation:
![a^{2} + b^{2} = c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%20c%5E%7B2%7D)
Assuming 20 is the hypotenuse cus there is no picture:
![a^{2} + 16^{2} = 20^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B%2016%5E%7B2%7D%20%3D%2020%5E%7B2%7D)
![a^{2} +256 = 400](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B256%20%3D%20400)
![a^{2} = 144](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%3D%20144)
![a=144](https://tex.z-dn.net/?f=a%3D144)
If It's not the hypotenuse:
![16^{2}+ 20^{2} =c^{2}](https://tex.z-dn.net/?f=16%5E%7B2%7D%2B%2020%5E%7B2%7D%20%3Dc%5E%7B2%7D)
![256+400 =c^{2}](https://tex.z-dn.net/?f=256%2B400%20%3Dc%5E%7B2%7D)
![656=c^{2}](https://tex.z-dn.net/?f=656%3Dc%5E%7B2%7D)
![c = 25.61249695](https://tex.z-dn.net/?f=c%20%3D%2025.61249695)
But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.
Hope this helped. :0)
To do that you'll need the mean and standard deviation of all the scores. Can you provide this info?
For example: Supposing that the mean of these scores were 52 and the standard deviation 3. You'd need to find the "z-score" of 57 in this case.
57 - 52
It is z = ------------ , or z = 5/3, or z = 1.67.
3
Find the area to the left of z = 1.67. Multiply that area by 100% to find the percentile rank of the score 57.