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alexgriva [62]
3 years ago
7

Simplify that answer

Mathematics
1 answer:
gogolik [260]3 years ago
5 0
3*squareroot(3) is the answer


2*sqrt(12) = 2*sqrt(4*3) = 2*sqrt(4)*sqrt(3) = 2*2*sqrt(3) = 4*sqrt(3)


sqrt(27) = sqrt(9*3) = sqrt(9)*sqrt(3) = 3*sqrt(3)


sqrt(48) = sqrt(16*3) = sqrt(16)*sqrt(3) = 4*sqrt(3)


therefore,

4*sqrt(3) + 3*sqrt(3) - 4*sqrt(3)

3*sqrt(3) + (4*sqrt(3)-4*sqrt(3))

3*sqrt(3)
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Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

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a) P(score greater than 615)

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P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%

b) b) P(score greater than 715)

P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

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c) P(score between 415 and 515)

P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%

P(415 \leq x \leq 515) = 34.1\%

d) P(score between 315 and 615)

P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%

P(315 \leq x \leq 615) = 81.8\%

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