Using the given table:
a) the average rate of change is 32.5 jobs/year.
b) the average rate of change is 12.5 jobs/year.
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How to find the average rate of change?</h3>
For a function f(x), the average rate of change on an interval [a, b] is:
a) The average rate of change between 1997 and 1999 is:
So the average rate of change is 32.5 jobs/year.
b) Now the interval is 1999 to 2001.
The rate this time is:
So the average rate of change is 12.5 jobs/year.
If you want to learn more about average rates of change:
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Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
Answer:
the goal is to try and get x alone. For the 1st problem, x=3.
Step-by-step explanation:
3x + 1 = 10 Subtract 1 both sides to cancel out the 1 on the left side. 10-1 = 9
3x = 9 To get x alone here, Divide 3 on both sides. 9/3 = 3
x = 3 Now x is alone, which means x = 3.
This is right because if you plug x with 3, the sum = 10.
(3*3) + 1 =10
9 + 1 = 10
So, that's how you know 3 is the right answer.
Answer:
sq rt 74 which is approx 8.6
Step-by-step explanation:
use distance formula
Answer:
Step-by-step explanation:
c.
y= 30x² +44x +16
factor
y= 2 (15x² +22x +8)
find zeros
15x²+22x+8=0
ax²+bx+c=0
x= (-b±√(b²-4ac))/2a
x= -22±√484-480/30 = -22±2/30 = -11±1/15
there are 2 zeros x= -10/15 ; x= -12/15
d.
y= 10x² +60x +80
factor
y= 10(x²+6x+8) = 10( x+2)(x+4)
finding zeros
x+2 =0 so x= -2
x+4 =0 so x= -4
there are 2 zeros x= -2; x= -4
