Answer:
A function to represent the height of the ball in terms of its distance from the player's hands is ![y=\frac{-1}{54}(x-18)^2+12](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-1%7D%7B54%7D%28x-18%29%5E2%2B12)
Step-by-step explanation:
General equation of parabola in vertex form ![y= a(x-h)^2+k](https://tex.z-dn.net/?f=y%3D%20a%28x-h%29%5E2%2Bk)
y represents the height
x represents horizontal distance
(h,k) is the coordinates of vertex of parabola
We are given that The ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.
So,(h,k)=(18,12)
Substitute the value in equation
---1
The ball leaves the player's hands at a height of 6 feet above the ground and the distance at this time is 0
So, y = 6
So,![6=a(0-18)^2+12](https://tex.z-dn.net/?f=6%3Da%280-18%29%5E2%2B12)
6=324a+12
-6=324a
![\frac{-6}{324}=a](https://tex.z-dn.net/?f=%5Cfrac%7B-6%7D%7B324%7D%3Da)
![\frac{-1}{54}=a](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B54%7D%3Da)
Substitute the value in 1
So,![y=\frac{-1}{54}(x-18)^2+12](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-1%7D%7B54%7D%28x-18%29%5E2%2B12)
Hence a function to represent the height of the ball in terms of its distance from the player's hands is ![y=\frac{-1}{54}(x-18)^2+12](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-1%7D%7B54%7D%28x-18%29%5E2%2B12)
Answer:
9
Step-by-step explanation:
i hope this is helpful........
I'm assuming the funds earn 5% yearly?
Call x the amount he saves every year. The first year's deposit will be multiplied by 1.05 three times, the next will be multiplied by 1.05 twice, the third will be multiplied by 1.05 once, and the fourth will not generate interest (as it will immediately be used to buy the car).
Therefore, x(1.05^3+1.05^2+1.05+1)=21000, so 4.31x=21000. Dividing by 4.31, we see that x is approximately equal to 4872.
Answer:
x 8 = 13.8564064606
Step-by-step explanation: The main diagonal of any cube can be found by multiplying the length of one side by the square root of 3 (
). Therefore, square root 3 (
) is multiplied by the length (8 in our case) of either 6 faces of the cube.
Hope it helped!