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valentina_108 [34]
3 years ago
15

How do I reflect (-4-3) over the y-axis?​ no links please

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

(4, -3)

Step-by-step explanation:

(-4, -3) reflected y-axis => (4, -3)

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Find the equation of the line given the slope and the y-intercept
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Answer:

y = \frac{1}{2}x + 3

Step-by-step explanation:

The equation for a linear graph is usually written in the following format...

y = mx + b

Where m would be the slope, usually referring to rise over run and b would be the y-intercept (where the line crosses the y-axis). From the graph, we can see that the line crosses the y-axis at point 3 so b would be 3. The graph also shows us that for every 1 value that the line rises it moves to the right 2 values. Therefore, the slope would be 1/2. Using these values we can create the following equation...

y = \frac{1}{2}x + 3

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Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti
ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a.3x+3y=8

Differentiate w.r.t x then we get

3+3\frac{dy}{dx}=0

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\frac{dy}{dx}=y'=-1

b.3x+3y=8

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Differentiate w.r.t x then we get

\frac{dy}{dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

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Answer:

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