Answer:
-27 is the answer of this problem
Answer:
4, 6, 1
Step-by-step explanation:
We can solve this problem using a system of equations:
1) a + b + c = 11
2) 2a + 5b + 6c = 44
3) 4a - b = 10
First, we can substitute the value of b from equation #3 into equation #1:
b = 4a - 10
a + (4a - 10) + c = 11
5a - 10 + c = 11
5a + c = 21
c = 21 - 5a
Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:
2a + 5(4a - 10) + 6(21 - 5a) = 44
2a + 20a - 50 + 126 - 30a = 44
-8a + 76 = 44
-8a = -32
a = 4
b = 4a - 10 = 4(4) - 10 = 6
c = 21 - 5a = 21 - 5(4) = 1
1 ticket costs $27, 2 tickets cost $54, 3 cost $81, 4 cost $108, and 5 cost $135.
There is a $27 difference between each ticket above or below
Answer:
10
Step-by-step explanation:
Do 40+8 first which is 48. then you think "what times four is 48" which is 12. so you need to add something to 2 to make 12. which is 10. A=10 :)
