Since the distance of MN is 31 and we have a distance of ML
of h -15 and LN of 2h – 8, therefore
ML + LN = h -15 + 2h – 8 = 31
h = 18
substituting the value of h to the expression for LN
obtaining
LN = 2h – 8
LN = 2(18) – 8
LN = 28
Therefore the length of the segment LN is 28 units
Answer:
see explanation
Step-by-step explanation:
∠ PQX = 90° ( angle in a semicircle )
∠ PXQ = 42° ( alternate angle theorem )
Angle between tangent and diameter is right, thus
∠ XPQ = 90° - 42° = 48°
Let's pick some simple points with which to set up an example for ourselves for this. Let's let the smaller radius be 1, and the larger, twice that, be 2. The radius itself is a single unit measure; in other words, it's measured as inches, feet, cm, etc., while the volume is a cubed measure. Volume is measured in inches cubed, feet cubed, cm cubed, etc. Therefore, if we have the radii measuring 1:2, we simply cube those single unit measures to find the ratio of their volumes. 1 cubed is 1, and 2 cubed is 8. So your answer for this is 1/8.
