Answer and Step-by-step explanation:
Given
ax + by = c
qx + ry = s
(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example
x + y = 3
x + y = 5
Subtracting first equation from the second we have:
0 = 2 which is impossible.
(b) the equations have infinite solutions if a/q = b/r = c/s, for example
x + y = 2
x + y = 2
Subtracting the first equation from the second we have
0 = 0, since this is always true, then it has infinite solutions.
(c) the equations have unique solutions if a/q ≠ b/r, for example
x + y = 2
x – y = 1
Adding the first and second equation we have
2x = 3, we can get x from here and definitely y, so we have just one solution.
Answer:
C) -9.6
Step-by-step explanation:
Answer:
The answer is -23
Step-by-step explanation:
Answer:
x = 
Step-by-step explanation:
Given
3x + k = c ( isolate the term 3x by subtracting k from both sides )
3x = c - k ( divide both sides by 3 )
x = 
1.25j+5.25 would be the answer. just combine like terms