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3 years ago

What is 12% of 79 ??

Mathematics

2 answers:

Rus_ich [418]3 years ago

8 0

12% Of 79 Would be 9.48. Hope this helped :)

xxMikexx [17]3 years ago

3 0

The to %12 of 79. The answer is 15

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Every year after a new car is

slavikrds [6]

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

6 0

3 years ago

The vertex of the parabola is at the point (2,-5). which of the equations below could be the one for this parabola?

timofeeve [1]

Hello,
Answer is Dsince y=k(x-2)²-5 and if k=1 ==>D.

7 0

3 years ago

Read 2 more answers

Three cards are drawn from a standard deck. What is the probability that all three are hearts, given that at least two of them a

bogdanovich [222]

Answer:

1/3 I believe because we already know 2 of them are hearts

Step-by-step explanation:

3 0

3 years ago

Texas chic. <br> This is for you

saw5 [17]

Ur outlier is 21

mean is : 5
deviation is 2.6

so ur answer is : 2nd one

8 0

2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

2 years ago