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strojnjashka [21]
2 years ago
5

Q is the midpoint of GH¯¯¯¯¯¯ , GQ=2x+3, and GH=5x−5 . What is the length of GQ¯¯¯¯¯ ?

Mathematics
1 answer:
trasher [3.6K]2 years ago
4 0
The length of GQ is 2 1/3 (two and one-third) where x equals -2/3 (negative two-thirds).
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Ber [7]

Answer:

7(x)=5x+7

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0=5x+7

move the left side and change the sign

-5x7

divide both of the equation by -5

x= -\frac75

same steps for g(x)=-2x-4

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Find the missing side of the triangle !!!<br> HELP MEEE!!!!!!!!!!!!!!
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The answer would be 10

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3 years ago
Which expressions are equivalent to √/32?<br> 4√8<br> 08<br> 2√8<br> 4√2<br> 16<br> 16√2
vaieri [72.5K]

Answer: 4√2

square root of a number is the factor that we can multiply by itself to get that number.

The square root symbol is also called as a RADICAL.

Perfect squares are the squares of the integers also called as square numbers.

to find the square root of non-perfect squared numbers we have to check the number with a near-perfect squared numbers

how to find square root of non perfect squared numbers:

If we can't figure out what factor multiplied by itself will result in the given number, we can make a factor tree.

Factor tree of 32 = 2*2*2*2*2

                            = (2*2) * (2*2) *2

                            = (4)2 *2

Therefore √/32 = √/2*2*2*2*2

                          = √/(4)2*2

                          = 4√/2

learn more about square roots here:

brainly.com/question/428672

brainly.com/question/3617398

#SPJ9

8 0
1 year ago
What is the volume of the rectangular prism?
Nataly_w [17]

Answer:

C. 72 cm^3

Step-by-step explanation:

Volume of rectangular prism is length times width times height

3 0
3 years ago
Read 2 more answers
Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

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4 0
1 year ago
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