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2 years ago

Anyone please help me

Mathematics

1 answer:

QveST [7]2 years ago

6 0

Standard form of a quadratic equation: ax^2 + bx + c = 0

4x^2 - 5x + 10 = 2x

4x^2 - 7x + 10 = 0

Hope this helps!

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Jose wants to have an average of 80 for his 4 exams. Each exam is scored on a scale of 0 to 100. His first three exam scores are

Oxana [17]

Answer:

Step-by-step explanation:

Assuming that all exams have the same weight, in order to achieve an average score of 80, the sum of all scores must equal 4 x 80. Therefore, the grade Jose needs in his last exam is:

$87+72+85+x=4*80\\x=76$

Jose needs to score a 76 in his last exam to have a mean of 80.

5 0

3 years ago

What is the value of X in the figure below? In this diagram.

kipiarov [429]

<h3>Answer: E. 45/4</h3>

===========================================

Work Shown:

Because we have similar triangles, we can form the proportion below to isolate x.

(AC)/(BC) = (CD)/(AC)

(15)/(20) = (x)/(15)

15*15 = 20x .... cross multiply

225 = 20x

20x = 225

x = 225/20

x = (5*45)/(5*4)

x = 45/4

3 0

3 years ago

A triangle has side lengths measuring 2x + 2 ft, x + 3 ft,

uysha [10]

Answer:

A is the answer on edgdenuity

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve for X. 3/4x+7/8=4 1/4 Enter your answer as a mixed number in simplest form in the box.

neonofarm [45]

Step-by-step explanation:

$\frac{3}{4} x + \frac{7}{8} = 4 \frac{1}{4}$

$\frac{3}{4} x = \frac{17}{4} - \frac{7}{8}$

$\frac{3}{4} x = \frac{34}{8} - \frac{7}{8}$

$\frac{3}{4} x = \frac{27}{8}$

$3x \times 8 = 27 \times 4$

$24x = 108$

$x = \frac{108}{24}$

$x = \frac{9}{2}$

6 0

2 years ago

Please explain your answer. THX!

Elden [556K]

Answer:

see explanation

Step-by-step explanation:

(3)

Given cosΘ = - $\frac{4}{5}$

Then by Pythagoras' theorem the third side is 3 ( 3,4, 5 triangle )

Since Θ in second quadrant then sinΘ > 0

sinΘ = $\frac{3}{5}$

Using the trigonometric identity

sin2Θ = 2sinΘcosΘ, then

sin2Θ = 2 × $\frac{3}{5}$ × - $\frac{4}{5}$ = - $\frac{24}{25}$

(4)

Using the trigonometric identity

cos(x - y) = cosxcosy + sinxsiny

note cos15° = cos(45 - 30)°

cos(45 - 30) = cos45cos30 + sin45sin30

= ( $\frac{\sqrt{2} }{2}$ × $\frac{\sqrt{3} }{2}$ ) + ( $\frac{\sqrt{2} }{2}$ × $\frac{1}{2}$ )

= $\frac{\sqrt{2(\sqrt{3}+1) } }{4}$

4 0

3 years ago