The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
Let C = the Chinese books.
Let E = the English language books.
C = 4/5 E
E - 300 = C - 180 Notice how you get this equation. You take 300 away from the English books and 180 from the Chinese and according to the question, you get an equal number of both. Put c = 4/5E into the second equation.
E - 300 = 4/5 E - 180 Add 300 to both sides.
E = 4/5 E - 180 + 300
E = 4/5 E + 120 Now subtract 4/5 E from both sidies.
E - 4/5 E = 120
1/5 E = 120 Now multiply by 5
E = 120 * 5
E = 600
So the number of books are
600 written in English
4/5 of 600 = 2400 /5 = 480 Chinese books.
English 600
Chinese 480
Answer:
16/15
Step-by-step explanation:
The two minus signs cancel, so the result is positive.
Answer:
Choice A
1/17; no, they are dependent events
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Explanation:
There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade
If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total.
Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17
The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.
Answer:
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