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rewona [7]
2 years ago
10

Someone please help me please

Mathematics
1 answer:
sertanlavr [38]2 years ago
7 0

Answer:

D.   (x - 2)(x + 2)

Step-by-step explanation:

Look at the graph, when y = 0, x = - 2 and x = 2, vertex = -4

OK so x = -2 means x + 2 = 0

and x = 2, means x - 2 = 0

So

answer :D.  (x - 2)(x + 2)

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Answer: x = 1

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7 0
3 years ago
Please help I am stuck on this
9966 [12]
Answer: B. y = 1/2x - 1

Explanation:
I know someone else already answered, but I wanted to explain why the answer is B.

Consider an equation of a line in slope-intercept form: y = mx + b

Since the line intersects the y-axis at -1, that’s the y intercept, or b. We know the slope of the line is positive because it slopes upward from left to right. From each whole number solution point, the line goes up one and two to the right. Slope, represented by m, is “rise” over “run”, or the change in y over the change in x. This makes the slope 1/2.

I hope this helps.
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2 years ago
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
LenKa [72]

Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

h(x)=In(3x - 1) then h'(x)=\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}

7 0
3 years ago
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