To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that
and the exponent
are divisible by index
. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is: 
Answer:
b $3,272.43
Step-by-step explanation:
A = p(1+r/n)^nt
Where
A= future value
P= principal = $2500
r= interest rate = 6.75% = 0.0675
n = number of periods = 12
t = time = 4 years
A = p(1+r/n)^nt
= 2500(1+0.0675/12)^12*4
= 2500(1+0.005625)^48
= 2500(1.005625)^48
= 2500(1.3089737859257)
= 3272.4344648144
Approximately
A= $3272.43
He will have $3272.43 to give as down payment in 4 years
Answer:
dy/dx = -1/
Step-by-step explanation:
y = 1/x
dy/dx = d/dx(1/x)
=> dy/dx = d/dx(
)
=> dy/dx = -
=> dy/dx = -1/
The third one would be the correct answer. I separately multiplied each number in the first section by each number in the second section. For instance, 0 x 2 is 0, 4 x 5 is 20, 5 x 3 is 15, and 2 x 0 is 0. All of these numbers are in the third answer.
Answer:
{(3, -1), (7, 1), (-6, -1), (9, 1), (2, -1)}
Step-by-step explanation:
Any relation having repetitive x-coordinates, is NOT a function.
