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True [87]
3 years ago
6

I was wondering if anyone could explain how to solve this?

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0
(a+b)² can also be written as (a+b) (a+b). When you expand this you get a²+2ab+b²

(a-b)² can also be written as (a-b) (a-b). When expanded this gives a²-2ab-b2

As you can see, this leads to different coefficients of the 'ab' values: for (a+B) ² its 2 for (a-b) ² its - 2
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Please help and show work
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For the triangles to be congruent

x=y+5 .......(substitute in the second equation)

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3 years ago
PLEASE IF YOU ARE SMART HELP ME WITH THIS PROBLEM. I WILL GIVE YOU EXTRA POINTS
raketka [301]
a_{n} = 2a_{n-1} + 3

a_{1} = 2

a_{2} = 2a_{2-1} + 3 = 2a_{1} + 3 = (2*2) + 3 = 4 + 3 = 7

a_{3} = 2a_{3-1} + 3 = 2a_{2} + 3 = (2*7) + 3 = 14 + 3 = 17

a_{4} = 2a_{4-1} + 3 = 2a_{3} + 3 = (2*17) + 3 = 34 + 3 = 37

a_{5} = 2a_{5-1} + 3 = 2a_{4} + 3 = (2*37) + 3 = 74 + 3 = 77

Hence, the first five terms are 2, 7, 17, 37, 77.
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Step-by-step explanation:

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