1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikklg [1K]
3 years ago
8

A rental car company has found that, on average, each customer drives 136 miles per day in a rental car. For each customer, the

company charges a daily base price of $41.02 and an additional $0.31 per mile traveled. What is the rental car company's mean charges per day for one customer?
Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

Company charges $83.18 per day for one customer.

Step-by-step explanation:

A rental car company charges a daily base price = $41.02

Additional charges for per mile travelling by the customer = $0.31

If a customer travels 'x' miles per day then the total per day charges of a car

= $(41.02 + 0.31x)

Now we know on average, each customer drives 136 miles per day.

So each day mean charges for one customer = $[41.02 + (0.31×136)]

= 41.02 + 42.16

= $83.18

Therefore, mean charges per day for one customer is $83.18.

You might be interested in
Beatrice has a rectangular swimming pool in her backyard. The dimensions are 16 feet by 8 feet. She decides to build a deck of u
xeze [42]
Super happy with. Long long long
5 0
2 years ago
Ms. Hernández is taking her children and their friends to the movies. She will pay $10 for her adult ticket and $7 for each chil
stiv31 [10]
(40-10)/7

The maximum amount of money she wants to spend is $40
Her adult ticket costs $10
She will pay for the children’s tickets with the remaining money
Each child’s ticket costs $7
To find the number of children she can take we need to use this expression (40-10)/7
Mrs Herñàndez can take 4 children
8 0
2 years ago
Read 2 more answers
Write an equation of the perpendicular bisector of the segment with end points M(1,5) and N(7,-1)
vitfil [10]
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

P=\dfrac{(1,5)+(7,-1)}{2}=\dfrac{(8,4)}{2}=(4,2)

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:

m_r=\dfrac{\Delta y}{\Delta x}=\dfrac{5-(-1)}{1-7}=\dfrac{6}{-6}\iff m_r=-1


p\perp r\Longrightarrow m_p\cdot m_r=-1\Longrightarrow m_p\cdot(-1)=-1\iff m_p=1

We can calculate the equation of p by using its slope and its point P:

y-y_P=m_p(x-x_P)\\\\
y-2=1\cdot(x-4)\\\\
y-2=x-4\\\\
\boxed{p:~~y=x-2}
4 0
3 years ago
5. Given: BCDF is a parallelogram; line AB is congruent to line BF
solong [7]
A and E are corresponding angles so A=E
3 0
2 years ago
The list shows the heights of some stickers in inches. The data will be put in a line plot
Zielflug [23.3K]

Answer:

The data should be from 1 to 2 with tick marks every 10th

Step-by-step explanation:

3 0
2 years ago
Other questions:
  • 6x^+4(x^-1) simply this question
    12·1 answer
  • A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c
    6·1 answer
  • A student concluded that the solution to the equation √2x+1+3=0 is x=4.
    11·2 answers
  • Draw a picture to show 9/7
    7·2 answers
  • 11. Find the slope of the following coordinate points: (11,4)<br> and (5.-3)
    8·2 answers
  • 6. Dakota got a job at IKEA. He will be getting paid $4.25 per hour for testing the sofas and beds. How much will he earn
    14·1 answer
  • What's 165% as a fraction and decimal
    5·1 answer
  • I need your help plz
    11·1 answer
  • A cylinder and a sphere both have the same radius, 4. The height of the cylinder is equal to the diameter of the sphere. Select
    13·1 answer
  • If p is inversely proportional to the square of q, and p is 16 when q is 11, determine p
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!