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2 years ago

7

it took jake 28 minutes to run 5km last months. this month he ran 5km in 21 minutes. by what percentage had jake improve his run

ning time?

2 answers:

mars1129 [50]2 years ago

6 0

Answer:

25%

Step-by-step explanation:

28-21=7

7/28=×/100

7×100=700

700÷28=25

anygoal [31]2 years ago

4 0

<em>Answer:</em>

<u><em>7</em></u>

Step-by-step explanation:

<em><u>Okay so, 28-21 =07 right</u></em>

<em><u>7 as a percent is 700% and the limit is 100% </u></em>

<em><u>so 700%/100%= 7</u></em>

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Solve the following inequality

Burka [1]

First we must get rid of the -3 in the denominator
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2x - 1 <span>< -5
now add 1 to both sides

2x </span><span>< -4

finally, divide both sides by 2

x </span><span>< -2

i hope this helps !!</span>

7 0

3 years ago

Put them in order from least to greatest:<br> 9.5 9.66 9.662 9.551 9 9.59 9.626

Fiesta28 [93]

Answer:

9, 9.5,9.551,9.59,9.626,9.66,9.662

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

steposvetlana [31]

<u>Answer-</u>

$f(2)= 6x^4-10x^3+40x-50=46$

<u>Solution-</u>

The given function is,

$\Rightarrow f(x)= 6x^4-10x^3+40x-50$

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= 96-80+80-50$

$\Rightarrow f(2)= 96-50$

$\Rightarrow f(2)= 46$

Therefore, f(2) was found to be 46.

7 0

3 years ago

Reduce to simplest form. <br> -7/12 +3/8

gayaneshka [121]

Answer:

ok so you should get -5/24 in simplest form.

Decimal form- -0.2083 repeating

Step-by-step explanation:

Hope this helped :)

4 0

2 years ago

tickets were sold at four different gates. Gate D sold 24%. Gate A sold 36%. Gate C sold 14%. Gate B sold 26%. If 39 tickets wer

Drupady [299]

Answer:

150 tickets

Step-by-step explanation:

Given: Tickets sold at four different gates

Gate B sold 26 % tickets

Tickets sold at Gate B = 39

Let take x as total number of tickets sold at all four gates.

Now, using the value of gate B to find total number of tickets

∴ $26\% \times total\ ticket\ sold = 39$

⇒ $\frac{26}{100} \times x = 39$

Next, cross multiply both side

⇒ $x= \frac{39\times 100}{26} = 150\ tickets$

∴ Total tickets sold at all the four gates is 150

5 0

3 years ago