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3 years ago

In 2010 the national debt was around 13,316,000,000,000 dollars. How would this number be written in scientific notation?

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

a) 1.33*10^13

Step-by-step explanation:

In scientific notation, we have the starting number which is between 1 and 10 which is multiplied by a power of 10.

The starting number is the first digit, then a decimal is placed with the next two digits. The power of 10 is determined by counting from 0 to the first digit.

So 1.33*10^13 is the answer

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PLEASE PLEASE HELP AND I NEED YOU TO DO IT FAST BECAUSE I HAVE TO GO SOON

Greeley [361]

The height is modelled by the equation:

$h(t)=-0.2t^2+2t$

Therefore

$\begin{gathered} \text{ } \\ \frac{\text{ dh}}{\text{ dt}}=-0.4t+2 \end{gathered}$

At the maximum height dh/dt = 0:

Hence,

$\begin{gathered} -0.4t+2=0 \\ -0.4t=-2 \\ \text{ Dividing both sides by -0.4} \end{gathered}$ $\begin{gathered} \frac{-0.4t}{-0.4}=\frac{-2}{-0.4} \\ t=5 \end{gathered}$

Hence, the ball gets to the maximum height after 5s.

The maximum height is given by h(5):

$h(5)=-0.2(5)^2+2(5)=5$

Therefore, the maximum height is 5 ft.

When the ball reaches the ground h(t) = 0:

$\begin{gathered} -0.2t^2+2t=0 \\ \text{ Dividing both sides by -0.2, we have:} \\ t^2-10t=0 \\ Factorising\text{ the left hand side, we have} \\ t(t-10)=0 \\ \text{ Therefore,} \\ t=0,\text{ t=10} \end{gathered}$

The ball reaches the ground in 10s

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1 year ago

What is midpoint of the segment whose endpoints are (-2,-3) and (6,1)?

denis23 [38]

(-2+6)/2=x
(4)/2=x
2=x
(-3+1)/2=y
(-2)/2=y
-1=y

The coordinate point is: (2,-1).

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3 years ago

Solve 3x + k = cfor x.

Ghella [55]

First, subtract k from both sides. That means c - k is in the left side and 3x is on the right. Then, divide by 3 on both sides. So, the answer is x = (c - k) / 3.

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4 years ago

Which of the following relations is a function?

Archy [21]

B is the correct answer

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3 years ago

Read 2 more answers

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

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2 years ago