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soldier1979 [14.2K]

3 years ago

13

An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is

48 feet. If each 16 feet of the lab equals 2 centimeters on a scale drawing, which of the following drawings is the scale drawing of the computer lab?

2 answers:

Gre4nikov [31]3 years ago

5 0

Answer:

The length of the rectangle is equal to 6 cm and the width is equal to 4 cm.

Step-by-step explanation:

Given is : The length of the lab is 32 feet and the width of the lab is 48 feet and each 16 feet of the lab equals 2 centimeters on a scale drawing.

So, We will divide the actual length with 16 and multiply by 2 as 16 feet is equal to 2 cm.

So, length will be = $\frac{48}{16} \times2$ = 6 cm

Width will be = $\frac{32}{16} \times2$ = 4 cm

Therefore, the length of the rectangle is equal to 6 cm and the width is equal to 4 cm.

just olya [345]3 years ago

3 0

The scale drawing of the computer lab will have a length of 4 centimeter and a widtgh of 6 centimeter.

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Jax and Sofia collect baseball cards. Jax has 56 cards and Sofia has 68. They each joined different baseball-collecting clubs. E

masya89 [10]

Jax gets 4 packs per month...each pack contains 4 cards...so he gets 16 cards per month.
Sofia gets 3 packs per month..each pack contains 4 cards...so she gets 12 cards per month..

56 + 16m = 68 + 12m
16m - 12m = 68 - 56
4m = 12
m = 12/4
m = 3.....they will have the same number of cards in 3 months

Jax : 56 + 16(3) = 104 cards
Sofia : 68 + 12(3) = 104 cards

and they will both have 104 cards

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2 years ago

Write the following quotient in the form a+bi.<br> -7i/2-7i

Helga [31]

Answer:

$\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}$

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

In the following, after distributing and solving, find the error.

larisa86 [58]

After 6x+48=72, you have to subtract 48 on both sides not add. Your final answer will be x=4. 72-48=24.. 24/6= 4.

8 0

3 years ago

F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.

Rom4ik [11]

Answer:

$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

$17.~g(f(-5))=\Large\boxed{1}$

$18.~f(g(-5))=\Large\boxed{-3}$

Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

$f(7)=(7)+4$

$f(7)=\Large\boxed{11}$

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

<u />

<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

$g(6.5)=2(6.5)+3$

$g(6.5)=13+3$

$g(6.5)=\Large\boxed{16}$

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

1 year ago

A gym has 200 members who pay $30 per month for unlimited use of the gym’s equipment. A survey of the members indicates that for

Bas_tet [7]

Given:

Current revenue = $6000

<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases

We are told to find f, when R(f) </span><span>< 6000

Since </span>R(f)= -100f^2+400f+6000

R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000

Subtract 6000 from both sides

-100f^2 + 400f + 6000 - 6000 < 6000 - 6000

-100f^2 + 400f < 0

⇒ 400f - 100f^2 < 0

Divide the equation by 100

400f/100 - 100f^2/100 < 0/100

4f - f^2 < 0

Add f^2 to both sides of the equation

4f - f^2 + f^2 < 0 + f^2

4f < f^2

Divide both sides by f

4f/f < (f^2)/f

4 < f

⇒ f > 4

⇒ f ≥ 5

Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>

8 0

3 years ago