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soldier1979 [14.2K]
3 years ago
13

An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is

48 feet. If each 16 feet of the lab equals 2 centimeters on a scale drawing, which of the following drawings is the scale drawing of the computer lab?
Mathematics
2 answers:
Gre4nikov [31]3 years ago
5 0

Answer:

The length of the rectangle is equal to 6 cm and the width is equal to 4 cm.

Step-by-step explanation:

Given is : The length of the lab is 32 feet and the width of the lab is 48 feet and each 16 feet of the lab equals 2 centimeters on a scale drawing.

So, We will divide the actual length with 16 and multiply by 2 as 16 feet is equal to 2 cm.

So, length will be = \frac{48}{16} \times2 = 6 cm

Width will be = \frac{32}{16} \times2 = 4 cm

Therefore, the length of the rectangle is equal to 6 cm and the width is equal to 4 cm.

just olya [345]3 years ago
3 0
The scale drawing of the computer lab will have a length of 4 centimeter and a widtgh of 6 centimeter.
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PLEASE HELP ASAP.
alexandr1967 [171]

Answer:

Y' = (-2, 4\frac{2}{3})

Step-by-step explanation:

Given

Y = (-3,7)

Scale\ Factor = (\frac{2}{3}x,\frac{2}{3}y)

Required

Determine Y'

Y' can be solved by multiplying the scale factor by Y

i.e.

Y' = Scale\ Factor * Y

For, the x coordinates.

Y' = \frac{2}{3}x

Where

x = -3

Y' = \frac{2}{3} * -3

Y' = \frac{-6}{3}

Y = -2

For the y coordinates:

Y' = \frac{2}{3}y

Where

y = 7

Y' = \frac{2}{3} * 7

Y' = \frac{14}{3}

Y' = 4\frac{2}{3}

Hence:

Y' = (-2, 4\frac{2}{3})

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3 years ago
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FrozenT [24]

Answer:

A. 5

B. 12

Step-by-step explanation:

What you do is you substitute -2 into the a and the 3 into the b.

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3(4)-15+8                                   2-(-10)

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