
Using the fact that cos is 2π-periodic, we have

That is,
for any
and integer
.

We get 2 solutions in the interval [0, 2π] for
and
,

Answer:
From largest to smallest: FG, FH, GH
Step-by-step explanation:
Given




Required
Order the sides in descending order
First, we need to solve for x.
Perimeter of FGH is calculated as thus:

Substitute values for FG, GH, FH and Perimeter

Collect Like Terms


Reorder

Divide through by 24


Substitute 4 for x in FG, GH and FH












In order of arrangement in descending order, we have:

Answer:
w = 60
Step-by-step explanation:
the midsegment SU is half the measure of side RV, then
SU = RV , so
w - 30 = w ( multiply through by 2 to clear the fraction )
2w - 60 = w ( subtract w from both sides )
w - 60 = 0 ( add 60 to both sides )
w = 60
Answer:
f(8)=34
Step-by-step explanation:
To solve, you just substitute x for 8
4(8) + 2
32 + 2
F(8) = 34
Answer:
88 is a solution to 1/8 x =11, since a solution means that x is equal to that number, so in this scenario, x=88. When substituted(88*0.125), the same answer, 11, is obtained.
Step-by-step explanation: