Ask question

Ask question

All categories

3 years ago

13

Angle A and angle B are supplementary angles. If m angle A = (5x+2) and m angle B = (8x+9) , then find the measure of angle B

1 answer:

otez555 [7]3 years ago

8 0

You first identify what supplementary angles are,angles that add up to 180.
5x+2+8x+9=180
17x+11=180-11
17x=169
x=169divided by 17
x=9.9411
x=10 when rounded into the next value
8x*10=80+989

You might be interested in

In the data set below, what is the range? 9, 4, 9, 2, 8, 2, 1

noname [10]

First put these in order from least to greatest.

1,2,2,4,8,9,9 is the correct order
Range is when we subtract the greatest value of our data set from the smallest so in our case it would be 9-1 which leaves us with our answer that 8 is your range.

7 0

3 years ago

Amiraneli [1.4K]

Answer:

A

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

6. – 4y + 8x = 32 for y

MatroZZZ [7]

Answer:

The answer is: y=2x−8

Step-by-step explanation:

Step 1: Add -8x to both sides.

8x−4y+−8x=32+−8x

−4y=−8x+32

Step 2: Divide both sides by -4.

−4y−4=−8x+32−4

y=2x−8

4 0

2 years ago

Read 2 more answers

Problem Solve for t.<br> 2(t+1) = 10

Svetllana [295]

t=4

explanation

2(t+1)=10

2t+2=10

2t=8

t=4

5 0

3 years ago

How many different twotwo-letter passwords can be formed from the letters

Anna [14]

Answer:

$70$

Step-by-step explanation:

GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.

TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.

SOLUTION:

Total number of different letters $=8$

for two two-letter passwords $4$ different are required.

Number of ways of selecting $4$ different letters from $8$ letters $=^8C_4$

$=\frac{8!}{4!4!}$

$=70$

Hence there are $70$ different two-letter passwords can be formed using $8$ letters.

5 0

3 years ago