Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Step-by-step explanation:
5(m+3)=5m+15
5m+15=5m+15
m=1
Answer: c I think
Step-by-step explanation:
Answer:
i. 15.4
ii.45.2
Step-by-step explanation:
correct me if im wrong
tnx
The corner of a shape where two side meet
