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Novay_Z [31]
1 year ago
6

Solve the equation.

Mathematics
1 answer:
Gelneren [198K]1 year ago
5 0

Answer:

x=-5/4 or x=9/4

Step-by-step explanation:

2 - 4x = -7

-4x = -7 - 2

-4x = -9

x = 9/4

or

2 - 4x = 7

-4x = 7-2

-4x = 5

x = -5/4

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A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the per
nekit [7.7K]

Answer:

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

6 0
3 years ago
If T(n)= 3n-1 what is the third term
irina [24]
T(3)=3(3)-1
T(3)=9-1
T(3)=8

answer is 8
8 0
3 years ago
Read 2 more answers
A dolphin was swimming 28 meters below the oceans surface.it changed its depth to avoid a predator and ended up 21 meters below
Harman [31]

Answer:

+7

Step-by-step explanation:

if you go from 28 to 21 you see there is a difference of 7 and sense the number is a smaller number now we know the dolphin went up more towards the surface there for there is a change of positive 7

28-21=7

6 0
3 years ago
If the measure of angle JKP is 3r + 12 and the measure of angle PKN is 4r - 2, what is the measure of angle JKN
il63 [147K]
Answer should be 108 would you mind sending a visual so I can be sure
8 0
2 years ago
Given m<12= 121 and m<6= 75, find the measure of each missing angle.
slava [35]

Answer/Step-by-step explanation:

Given:

m<12 = 121°

m<6 = 75°

a. m<1 = m<6 (vertical angles)

m<1 = 75° (substitution)

b. m<12 = m<1 + m2 (alternate exterior angles)

121° = 75° + m<2 (substitution)

121° - 75° = m<2 (subtraction property of equality)

46° = m<2

m<2 = 46°

c. m<1 + m<2 + m<3 = 180° (angles on a straight line)

75° + 46° + m<3 = 180° (substitution)

121° + m<3 = 180°

m<3 = 180° - 121° (subtraction property of equality)

m<3 = 59°

d. m<4 = m<3 (vertical angles)

m<4 = 59° (substitution)

e. m<5 + m<4 + m<6 = 180° (angles on a straight line)

m<5 + 59° + 75° = 180° (substitution)

m<5 + 134° = 180°

m<5 = 180° - 134° (Subtraction property of equality)

m<5 = 46°

f. m<7 = m<12 (vertical angles)

m<7 = 121° (substitution)

g. m<8 = m<4 (vertical angles)

m<8 = 59° (substitution)

h. m<9 = m<6 (Alternate Interior Angles)

m<9 = 75° (substitution)

i. m<10 + m<9 = 180° (Linear Pair)

m<10 + 75° = 180° (substitution)

m<10 = 180° - 75° (Subtraction property of equality)

m<10 = 105°

j. m<11 = m<8 (vertical angles)

m<11 = 59° (substitution)

k. m<13 = m<10 (vertical angles)

m<13 = 105° (substitution)

l. m<14 = m<9 (vertical angles)

m<14 = 75° (substitution)

5 0
3 years ago
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