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4 years ago

Number 33? Help with a and b

Mathematics

1 answer:

Flura [38]4 years ago

7 0

You have to set it up clearly and cleanly and neatly.

a).
3 and 1/4 = 13/4 = 26/8
2 and 1/2 = 5/2 = 20/8
5/8 = 5/8

Add the eighths: (26 + 20 + 5)/8 = 51/8 = 6 and 3/8

b).
We want to know how many times 1/4 goes into the total amount.
51/8 = 25.5/4

That's 25 full servings, with 1/2 serving left over.
==============================================

For me, this whole thing is much easier if you work it in decimals.

a).
3 and 1/4 = 3.25
2 and 1/2 = 2.50
5/8 = . . . . . 0.625

Add um up: 6.375 quarts

b).
A serving is 0.25 quart.
Divide 6.375 by 0.25 = 25.5 . . . 25 full servings, with 1/2 left for the kitchen help.

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Can you be more specific?

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3 years ago

Write (5,0) with a slope of 2 in slope-intercept form

tia_tia [17]

Y = mx + c
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3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

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2 years ago

What is a GPA? How is it calculated and determined? If a person is required to have a GPA 95 or higher, what does that mean?

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Answer:

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Step-by-step explanation:

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