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tatiyna
3 years ago
7

Part 1: Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Id

entify the values of a, b, and c, and find the solutions using the quadratic formula.
Part 2: Using complete sentences, explain how you know that the equation from Part 1 cannot be solved by factoring, but can be solved by using the quadratic formula.
Mathematics
2 answers:
liq [111]3 years ago
8 0
Part 1: x^2 - 5x -3 =2 where a is equal to 1, b is equal to -5 and c is equal to -5. It cannot be factored because we need 2 integers that will yield a product equal to -5 and the sum of the integers is equal to -5. Using the quadratic formula, we will obtain answers equal to:
<span>
x1 = (5+3</span><span>√</span><span>5)/2
</span><span>x2 = (5-3</span><span>√</span><span>5)/2 </span>
eimsori [14]3 years ago
7 0
when you use all prime, non-one numbers for b and c, it cannot be factored most of the time


example
1x^2+7x+5
a=1
b=7
c=5
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
x=\frac{-7+/- \sqrt{7^2-4(1)(5)} }{2(1)}
x=\frac{-7+/- \sqrt{49-20} }{2}
x=\frac{-7+/- \sqrt{29} }{2}
x=\frac{-7+ \sqrt{29} }{2} or \frac{-7- \sqrt{29} }{2}



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Umnica [9.8K]
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3 years ago
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leva [86]

Answer:

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Step-by-step explanation:

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3 years ago
Please help with 15, 17 and 19
Irina-Kira [14]

Given:

15. \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

17. \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

19. 2^{\log_2100}

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)

Using property of logarithms, we get

\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1         [\because \log_aa=1]

Therefore, the value of \log_{\frac{1}{2}}\left(\dfrac{1}{2}\right) is 1.

17. We have,

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)

Using properties of logarithms, we get

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)                    [\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]

\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1                 [\because \log_aa=1]

Therefore, the value of \log_{\frac{3}{4}}\left(\dfrac{4}{3}\right) is -1.

19. We have,

2^{\log_2100}

Using property of logarithms, we get

2^{\log_2100}=100          [\because a^{\log_ax}=x]

Therefore, the value of 2^{\log_2100} is 100.

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mash [69]

3/4=(k+3)/9

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5 0
3 years ago
Help no links!!!!!!!!!!!!!!
Softa [21]

Answer:

7.

A.) -⅔

B.) 3/-2

Step-by-step explanation:

from 1 to -1 you have to go down 2

from 2 to -1 you have to go down 3

therefore your slope is -⅔

from 3 to 6 you go up by 3

from 1 to -1 you go down by 2

therefore your slope is 3/-2

8 0
2 years ago
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