Answer:
AND ![y=-\frac{3-\sqrt{5}}{2}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B3-%5Csqrt%7B5%7D%7D%7B2%7D)
Step-by-step explanation:
Given: ![y^2+3y=-1](https://tex.z-dn.net/?f=y%5E2%2B3y%3D-1)
To solve for
, we need to get everything on one side of the equal sign and set it to zero. We can do this by adding 1 to both sides. We then get:
![y^2+3y+1=0](https://tex.z-dn.net/?f=y%5E2%2B3y%2B1%3D0)
We can solve for
by using the quadratic formula:
AND ![y=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2a}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-b-%5Csqrt%7B%28b%29%5E2-4%28a%29%28c%29%7D%7D%7B2a%7D)
Let's identify our values:
![a: 1\\b: 3\\c: 1](https://tex.z-dn.net/?f=a%3A%201%5C%5Cb%3A%203%5C%5Cc%3A%201)
Plug in the values and simplify.
![y=\frac{-3+\sqrt{(3)^2-4(1)(1)}}{2(1)}\\y=\frac{-3+\sqrt{5}}{2}\\-------------------------\\y=\frac{-3-\sqrt{(3)^2-4(1)(1)}}{2(1)}\\\\y=\frac{-3-\sqrt{5}}{2}\\](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-3%2B%5Csqrt%7B%283%29%5E2-4%281%29%281%29%7D%7D%7B2%281%29%7D%5C%5Cy%3D%5Cfrac%7B-3%2B%5Csqrt%7B5%7D%7D%7B2%7D%5C%5C-------------------------%5C%5Cy%3D%5Cfrac%7B-3-%5Csqrt%7B%283%29%5E2-4%281%29%281%29%7D%7D%7B2%281%29%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-3-%5Csqrt%7B5%7D%7D%7B2%7D%5C%5C)
Your final answers are:
AND ![y=-\frac{3-\sqrt{5}}{2}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B3-%5Csqrt%7B5%7D%7D%7B2%7D)
The equations y = 3x - 4 and y = 3x + 1 are linear equations
The equations have no solution
<h3>How to determine the solution of the equations?</h3>
The equations are given as:
y = 3x - 4
y = 3x + 1
Next, we plot the graph of the equations y = 3x - 4 and y = 3x + 1
From the graph (see attachment), we can see that the equations do not have a point of intersection
Hence, the equations has no solution
Read more about linear equations at:
brainly.com/question/14323743
Y=4 (x+ 17/8)^2 - 657/16 hope this helps you out mate =)
Answer:
6+n/8=2
Step-by-step explanation:
* More Than = (+) or in some cases (>)
* Quotient of a (#) = Any letter that represents a number, so in this case "n", because we do not know that number yet. We divide this with "8" because it says "and 8".
* Equal = <---
Answer:
I THINK IT IS C
Step-by-step explanation:
I REMEMBER DOING THIS, SORRY IF IM WRONG HAVE A NICE DAY!