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3 years ago

Help Please!!!!!!!!!!

Mathematics

1 answer:

LenKa [72]3 years ago

5 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x+3y\leq 6$

Isolate the variable y

$3y\leq 6-x$

$y\leq 2-(1/3)x$

The solution is the shaded area below the solid line

Is below because the symbol of the inequality is less

Is a solid line because the line is included in the solution

The equation of the solid line is $y=2-(1/3)x$

To graph the solution find the intercepts

Find the x-intercept (value of x when the value of y is equal to zero)

For y=0, x=6 --------> point (6,0)

Find the y-intercept (value of y when the value of x is equal to zero)

For x=0, y=2 -------> point (0,2)

Graph the inequality

see the attached figure

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3 years ago

Algebra help please?

mezya [45]

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= w(w + 6) 6(w + 6)

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In short, Your Answer would be: Option D

Hope this helps!

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3 years ago

What is the sum of the infinite geometric series 9−6+4−83+...9-6+4-83+...??

vivado [14]

Successive terms have a common factor of $-\dfrac23$ , which means the $n$ th partial sum of the series can be written as

$S_n=9-6+4-\dfrac83+\cdots+9\left(-\dfrac23\right)^{n-1}$
$S_n=9\left(1+\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\cdots+\left(-\dfrac23\right)^{n-1}$

$\implies-\dfrac23S_n=9\left(\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\left(-\dfrac23\right)^4+\cdots+\left(-\dfrac23\right)^n\right)$

$\implies S_n-\left(-\dfrac23\right)S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
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As $n\to\infty$ , the geometric term vanishes, leaving you with

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3 years ago

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Brrunno [24]

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3 years ago

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dimulka [17.4K]

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b=b (the leg we need to find)
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$39^2 + b^2 = 89^2$
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(subtract the 1521 from both sides)
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(square root both sides)
$\sqrt{(b^2)} = \sqrt{6400} 
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3 years ago

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