Definitely.
But the two numbers have to be 6 and zero.
Answer:
The probability of selecting a non-defective part provided by supplier A is 0.807.
Step-by-step explanation:
Let <em>A</em> = a part is supplied by supplier A, <em>B</em> = a part is supplied by supplier B and <em>D</em> = a part is defective.
<u>Given</u>:
P (D|A) = 0.05, P(D|B) = 0.09
A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.
Then the probability of event <em>A</em> and <em>B</em> is:

Compute the probability of selecting a defective product:

The probability of selecting a non-defective part provided by supplier A is:

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.
2 hamburger + 1 milk =5
1 hamburger + 2 milk =5-.25
1 hamburger + 2 milk =4.75
multiply this by -2
-2hamburger + -4 milk =-9.5
add the first equation
-2 hamburger + -4 milk =-9.5
2 hamburger + 1 milk =5
---------------------------------------
-3 milk = -4.5
divide by -3
milk = 1.50
Answer: milk $1.50
Answer:
4.5 and 6
Step-by-step explanation: