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frosja888 [35]
3 years ago
5

What is the value of x?

Mathematics
1 answer:
alexdok [17]3 years ago
3 0
It should be 44ft bc 22ft and 22ft is 44ft
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What is the center of the equation (x+12)^2 + (y-9)^2= 35
Reil [10]

Answer:

(-12,9)

Step-by-step explanation:

The equation of a circle is given by the equation (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center point on the graph.

Therefore, in the equation (x+12)^2 + (y-9)^2 = 35, the center point on the graph would be (-12,9).

4 0
2 years ago
Please help me solve this question. Will make you the
lawyer [7]

Yes because if you graph it, it will pass the vertical line test

4 0
3 years ago
Choose the correct written expression for: 25 – (3 x 4).
netineya [11]

Answer:

13

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
Hope someone help.me​
zvonat [6]

x = r sin θ cos Ф

x² = r² sin² θ cos² Ф

y = r sin θ sin Ф

y² = r² sin² θ sin² Ф

z = r cos θ

z² = r² cos²  θ

x² + y² + z²

= r² sin² θ cos² Ф  +  r² sin² θ sin² Ф +  r² cos²  θ

= r² sin² θ (cos² Ф + sin² Ф) +  r² cos²  θ

= r² sin² θ + r² cos²  θ

= r² (sin² θ + cos²  θ)

= r²       √

7 0
3 years ago
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