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Ray Of Light [21]
3 years ago
11

What is the volume of 1.9 moles of chlorine gas (Cl2) at 298 K and 1.3 atm?

Chemistry
1 answer:
matrenka [14]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The correct option is option C.

V=36L

<h2>Why?</h2>

To calculate the volume of the gas sample, we need to use the Ideal Gas Law, this equation is used to relate the pressure, the volume, the mass and the temperature of a gas, so, we can isolate the volume from it.

The Ideal Gas Law equation is equal to:

PV=nRT

Where,

P is the pressure (in atm)

V is the volume (in liter)

n is the mass of the gass (in mole)

T is the temperature of the gass (absolute temperature)

So, from the statement we know that:

Pressure=1.3atm\\Temperature=298K\\n=1.9moles\\R=0.082057\frac{L.atm}{mol.K}

Then, substituting and calculating we have:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1.9moles*0.082057\frac{L.atm}{mol.K}*298K}{1.3atm}=35.74L

Now, rounding to the nearest whol number we have that the volume is equal to 36 L.

Hence, the correct option is option C.

Have a nice day!

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A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli
vladimir1956 [14]

Answer:

109.09°C

Explanation:

Given that:

the capacity of the cooling car system = 5.6 gal

volume of solute = volume of the water; since a 50/50 blend of engine coolant and water (by volume) is used.

∴ \frac{5.60}{2}gallons = 2.80 gallons

Afterwards, the mass of the solute and the mass of the water can be determined as shown below:

mass of solute = (M__1}) = Density*Volume

                          = 1.1g/mL *2.80*\frac{3785.41mL}{1gallon}

                         = 11659.06grams

On the other hand; the mass of water = (M__2})= Density*Volume

                         = 0.998g/mL *2.80*\frac{3785.41mL}{1gallon}

                        = 10577.95 grams

Molarity = \frac{massof solute*1000}{molarmassof solute*massofwater}

              =  \frac{11659.06*1000}{62.07*10577.95}

              = 17.757 m

              ≅ 17.76 m

∴  the boiling point of the solution is calculated using the  boiling‑point elevation constant for water and the Molarity.

\Delta T_{boiling} = k_{boiling}M

where,

k_{boiling} = 0.512 °C/m

\Delta T_{boiling} =  100°C + 17.56 × 0.512

              = 109.09 °C

6 0
4 years ago
Where was copper discovered? What country? pLeAse halp yall
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A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f
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Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

           S = K_{b} \times ln \Omega

where,      S = entropy

             K_{b} = Boltzmann constant

             \Omega = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

     \Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega

                 = 1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)

                 = 1.38 \times 10^{-23} \times (-0.182)

                 = -0.251 \times 10^{-23}

or,             = -2.51 \times 10^{-24}

Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

8 0
3 years ago
The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding
kirza4 [7]

Answer:  Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{Nhc}{\lambda}

where,

E = energy of the wave  = 182 kJ/mol  = 182000 J/mol

N = avogadro's number =  6.023\times 10^{23}

h = plank constant = 6.6\times 10^{-34}Js^{-1}

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of the wave = ?

Putting all the values:

182000=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^8m/s}{\lambda}

\lambda=0.65\times 10^{-6}m=650nm    (1nm=10^{-9}m)

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

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