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2 years ago

Which example shows a learned and an inherited behavior of a dog?

Chemistry

1 answer:

Arisa [49]2 years ago

4 0

Answer:

Explanation:

because dogs don't do c,The owner trains the dog to do a,d and b is naturally learned

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Which best describes a compound such as sodium chloride

Elza [17]

It is a compound composed of sodium (Na) and chloride (Cl)

5 0

3 years ago

Which type of bond is formed between atoms of solid gold

goldfiish [28.3K]

Answer:

covalent bonds

Explanation:

5 0

3 years ago

Read 2 more answers

Consider the following mechanism.

solong [7]

Answer :

(a) The overall equation is:

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

(b) The intermediates are :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$

Explanation :

Part (a) :

(1) $ClO^-(aq)+H_2O(l)\rightarrow HClO(aq)+OH^-(aq)$ (fast)

(2) $I^-(aq)+HClO(aq)\rightarrow HIO(aq)+Cl^-(aq)$ (slow)

(3) $OH^-(aq)+HIO(aq)\rightarrow H_2O(l)+IO^-(aq)$ (fast)

By adding the three equations and cancelling the common terms on both side, we will get the overall equation.

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

Part (b) :

Intermediates are generated and consumed in the mechanism and do not include in the overall equation.

Since, intermediates will not include in the overall mechanism.

The intermediates are :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$

7 0

3 years ago

"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the

soldier1979 [14.2K]

Answer: The specific heat of calorimeter is 30.68 J/g°C

Explanation:

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of hot water = 46.7 g

$m_2$ = mass of cold water = 45.33 g

$T_{final}$ = final temperature = 59.4°C

$T_1$ = initial temperature of hot water = 80.6°C

$T_2$ = initial temperature of cold water = 40.6°C

$c_1$ = specific heat of hot water = 4.184 J/g°C

$c_2$ = specific heat of cold water = 4.184 J/g°C

$c_3$ = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

$46.7\times 4.184\times (59.4-80.6)=-[(45.33\times 4.184)+c_3](59.4-40.6)$

$c_3=30.68J/g^oC$

Hence, the specific heat of calorimeter is 30.68 J/g°C

6 0

3 years ago

Draw the lewis structure of the hypochlorite ion clo- . include lone pairs

Dmitry_Shevchenko [17]

Solution:- Hypochlorite ion $ClO^-$ has one Cl and one O atom. Cl has 7 valence electrons and O has 6 valence electrons. Since there is one negative charge on the ion,

total valence electrons = 7 + 6 +1 = 14

(note:- if there is negative charge then it is added and if there is positive charge then it is subtracted while calculating the valence electrons)

Both Cl and O atoms wants to complete their octet and so for this we put a single bond between them. Single bond means two electrons, so the remaining electrons would be 14 - 2 = 12

It means 12 electrons will be placed as lone pair of electrons. To complete the octet, we put 6 dots around each of the atom. Oxygen is more electron negative than Cl, so we show the -1 charge for oxygen.

6 0

3 years ago