Answer:
A = 3
B = -5
C = 2
Step-by-step explanation:
The way to format a quadratic equation is:
, so the first step to solving this is to format it in the right way, where the
comes first, the
second, and the number alone.
After formatting, your equation should look like this: 
From here, you can see the the <em>a </em> is 3, the <em>b</em> is -5, and the <em>c </em>is 2
Answer:
The answer is 3
Step-by-step explanation:
7.5 m
---------
5
7.5(2)=15
-------------
5
15
--- =3
5
Exact form- 7/2
Decimal form- 3.5
Mixed number form- 3 1/2
I hope that helps!!!
Answer:
5.8%
Step-by-step explanation:
Current yield = 6.1%
Face value of bond = $500
Market price of bond = $475
Let the original coupon rate be CR


Multiply both sides by 475

Cancel out the 475's from the top and bottom of the right side


Flip the sides

Divide both sides by 5000

Cancel out 50000 from the top and bottom of the left side
%
CR = 0.0579 * 100 [convert decimal into a percentage]
CR = 5.79 %
CR = 5.8% [rounded off to the tenth place]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g