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salantis [7]
3 years ago
10

A cone has a volume of 1808.64 cubic inches and a height of 12 inches. What is its radius?

Mathematics
2 answers:
viva [34]3 years ago
5 0

Answer:

answer is 12. they may want it in format of 12.00

Zigmanuir [339]3 years ago
4 0

Answer:

r ≈ 12 inches

Step-by-step explanation:

Volume of Cone= V=πr^2h/3

or, 1808.64 =πr^2* 12/3

or, 1808.64 =πr^2* 4

or,1808.64/4π=r^2

or,√143.93 ≈ r

r ≈ 12 inches

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Austin was budgeted $ 825 to spend on chairs for his upcoming event. If each chair costs $ 15 , how many chairs can he purchase?
ElenaW [278]

Answer:

55 chairs

Step-by-step explanation:

825/15=55

5 0
3 years ago
The function g(x) = p sin x +q, where p>0, has a maximum value of 10 and a minimum value of -4. Find the value of p and of q.
tester [92]

Answer: p=7, q=3

Step-by-step explanation:

The midline of the function is

\frac{10-4}{2}=3 \implies q=3

This means that to obtain a maximum of 10, when \sin x reaches it's maximum, 1, g(x)=p+q=10 \implies p=7

7 0
2 years ago
What is the quotient? (9b2 – 3b) ÷ b
rosijanka [135]

Answer:

the answer is

9b²-3b

Step-by-step explanation:

9b-3

7 0
3 years ago
I need to know the answer
Nesterboy [21]

Answer in the attachment.

3 0
3 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
3 years ago
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