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Lilit [14]
3 years ago
13

suppose it takes 48 chickens fingers to feed Mr . Youngs 4th grade class of 20 students how many chicken fingers would be needed

for 30 students
Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0
30 is 1.5 times greater than 20 so 48*1.5 = 72
it would take 72 chicken fingers to feed 30 students
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How many blue circles are equivalent to the orange square? Explain how you know.​
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Answer:

5 blue circles are equivalent to the orange square

Step-by-step explanation:

If you take away 2 blue circles from each side so that the orange square is by it's self, and the equation stays balanced, you will be left with 5 blue circles on the side without the orange square.

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An animator draws 120 cels to make a 5 seconds of a 12-second sequence of a film. How many more cels does she need to draw to co
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Answer:

She needs 168 more cels to draw to complete the film sequence

Step-by-step explanation:

120 Cells in 5 seconds

You want 12 seconds.

Ratio (Proportion)

120:5

Lets find the "unit rate" of the proportion.

120/5 = 24

So the unit ratio is 24:1

Now, we can deduce to it being:

120:5

240:10

264:11

288:12

She has 120 done.

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4 0
2 years ago
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Answer:77

Step-by-step explanation:

Least Common Multiple of 7 and 11 with GCF Formula

The formula of LCM is LCM(a,b) = ( a × b) / GCF(a,b).

We need to calculate greatest common factor 7 and 11, than apply into the LCM equation.

GCF(7,11) = 1

LCM(7,11) = ( 7 × 11) / 1

LCM(7,11) = 77 / 1

LCM(7,11) = 77

Least Common Multiple (LCM) of 7 and 11 with Primes

Least common multiple can be found by multiplying the highest exponent prime factors of 7 and 11. First we will calculate the prime factors of 7 and 11.

Prime Factorization of 7

Prime factors of 7 are 7. Prime factorization of 7 in exponential form is:

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Prime Factorization of 11

Prime factors of 11 are 11. Prime factorization of 11 in exponential form is:

11 = 111

Now multiplying the highest exponent prime factors to calculate the LCM of 7 and 11.

LCM(7,11) = 71 × 111

LCM(7,11) = 77

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3 years ago
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