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Phoenix [80]
2 years ago
15

Your friend claims that when a polynomial function has a leading coeffcient of 1 and the coefficients are all integers , every p

ossible rational zero is an integer . Is your friend correct ? Explain your reasoning.
Mathematics
1 answer:
sammy [17]2 years ago
8 0

Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>
  • It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every <u>possible rational root</u> is the format \frac{p}{q}.

In this problem:

  • The leading coefficient is 1, hence it's only factor is q = 1, thus guaranteeing that every possible rational zero is an integer, which means that your friend is correct.

To learn more about the rational root theorem, you can take a look at brainly.com/question/10937559

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diketahui luas permukaan kubus 864 cm2. perbandingan rusuk kubus dan p balok 3 : 4 perbandingan p l dan tinggi 4:3:2 luas permuk
Kryger [21]
S2= 864/6
s = = 12 cm
p = 4/3 x 12 = 16 cm
t = 2/4 x 16 = 8 cm
l= 3/4x 16 = 12 cm

lp= 2 (pl+pt+lt)
= 2 (16 x 12 + 16 x 8 + 12 x8)
= 2 (192+128+96) = 832cm²
3 0
4 years ago
Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4
ad-work [718]

Answer:

f''(x)=36x^2+4

Step-by-step explanation:

Let's start by finding the first derivative of f(x)= 3x^4+2x^2-8x+4. We can do so by using the power rule for derivatives.

The power rule states that:

  • \frac{d}{dx} (x^n) = n \times x^n^-^1

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

  • \frac{d}{dx} (3x^4+2x^2-8x+4)

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)

Simplify the equation.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)
  • f'(x)=12x^3+4x-8

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

  • \frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)
  • \frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)

Simplify the equation.

  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )

Therefore, this is the 2nd derivative of the function f(x).

We can say that: f''(x)=36x^2+4

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The answer is a rectangle or a square.
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