Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
1+1 = 2
Step-by-step explanation:
3+4 = 7
so
21 / 7 3
3 x 3 = 9
3 x 4 = 12
answer
£21 in ratio 3:4 is £9:£12
For this case, we have by definition that, the median of a set of numbers is the average number in the set, after the numbers have been ordered from lowest to highest. If there is an even number in the set, the median is the average of the two middle numbers.
So, the given set is:
{4,5,5,6,10,11,12,13}
Since there are 8 numbers, the set is even. Then we find the average of the two numbers in the middle:

The median is 8
ANswer:
8