Answer:
255 m
Step-by-step explanation:
From the given question, the surface of the water body is the reference point. And this point is assumed to be 0, so that any distance above it is positive, and any distance below is negative. This is synonymous to the number line system.
Thus,
For the aircraft, its height = +200 m
For the submarine, its depth = -55 m
So that the difference between the submarine and aircraft can be determined as;
200 - (-55)
= 200 + 55
= 255 m
The distance between the submarine and aircraft is 255 m.
15y is less than 36+9
y is less than 45/15
y is less than 3
Answer:
3x³ and 6x³, y and 7y
Step-by-step explanation:
Like terms have variables with the same exponents. This fact eliminates choices A, C, D.
The like terms are ...
3x³ and 6x³, 7y and y . . . . . . choice B
A a b...............................
C = circumference of circle
p = perimeter of square
c + p = 29
p = 29 - c
side of square = (29 - c)/4
radius of circle = c/(2pi)
a = side^2 + (pi)r^2
a = ((29 - c)/4)^2 + pi * (c/(2pi))^2
a = (1/16)(841 - 58c + c^2) + (c^2/(4pi^2)) * pi
a = 52.5625 - 3.625c + c^2/16 + c^2/(4pi)
Since the 2nd degree term has a positive coefficient is positive, this has a graph that is a parabola opening up. It has a minimum value.
We take the derivative of the area expression and set equal to zero to find the minimum circumference.
da/dc = -3.625 + c/8 + (c/(2pi)) = 0
c = 12.76
Answer: 12.76 cm
