What is the point slope of the line when slope is -4 and the given coordinates are (4,-9)
1 answer:
The point-slope form of the equation of a straight line is:

We have:

Substitute:

You might be interested in
Answer:
y = 7/8x + 6
-Hope This Helps
Answer:
5= b 6=d
Step-by-step explanation:
Answer:
quadrillion, hope this helps
Step-by-step explanation:
Answer:
where is the following
Step-by-step explanation:
b i can teve n tse the following answers
Answer:
Step-by-step explanation:
