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Inga [223]
3 years ago
6

What is the area?? Please help

Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Answer:

<h3>324 ft²</h3>

Step-by-step explanation:

We have the triangle and the rectangle.

The formula of an area of a triangle:

A_{\triangle}=\dfrac{1}{2}bh

b - base

h - height

The formula of an area of a rectangle:

A_{\boxed{\ }}=lw

l - length

w - width

We have b = 24 ft, h = 7 ft, l = 24 ft and w = 10 ft.

Substitute:

A_\triangle=\dfrac{1}{2}(24)(7)=(12)(7)=84\ ft^2

A_{\boxed{\ }}=(24)(10)=240\ ft^2

The area of the figure:

A=A_{\triangle}+A_{\boxed{\ }}

Substitute:

A=84+240=324\ ft^2

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Tom ate 1/6 in the morning and 3/6 in the afternoon. How much of the bread did he eat?
frozen [14]

Answer:

4/6 or 2/3

Step-by-step explanation:

Amount of bread Tom ate= Tom ate in morning + Tom ate in evening

                                          = 1/6 + 3/6

                                          = 3+1/6

                                          = 4/6

                                          = 2/3

5 0
3 years ago
Please help! i’ll give brainliest! thank u!
Ivenika [448]

Answer:

Negative with little correlation

It has negative slope if you imagine a line

8 0
3 years ago
How do you find the markup rate?
andrezito [222]

Answer: Simply take the sales price minus the unit cost, and divide that number by the unit cost. Then, multiply by 100 to determine the markup percentage. For example, if your product costs $50 to make and the selling price is $75, then the markup percentage would be 50%.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
3 years ago
There are approximately 3.2
gladu [14]
So, using the number 3,200,000 deaths per year, you want to divide it until it reaches deaths per minute.
3,200,000 divided by 365 (for days)
8767.123 divided by 24 (for hours)
365.297 divided by 60 (for minutes)
and so you get 
6.088 deaths per minute

Hope this helped.
8 0
3 years ago
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