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Paha777 [63]
4 years ago
10

Your company took a start up loan at 5% interest. You also took a capital improvement loan for 7% interest. The start up loan is

eight times larger than the improvement loan. If the interest paid on both loans for one year is $9,400, how much did the company borrow for each loan?
Mathematics
1 answer:
snow_tiger [21]4 years ago
6 0
To answer the question above, we let 8x be the amount loaned with 5% interest and x be the amount loaned at 7% interest. The amount of interest is calculated through the equation,
                                     I = amount x rate 
The sum of these interest should be 9,400. The equations that would best represent the given scenario are,
              (8x)(0.05) + x(0.07) = 9400
The value of x from the given equation is,
                              x = 20,000
Therefore, the company loaned $160,000 with 5% interest and $20,000 with 7% interest. 
                               
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What value of x <br> in the solution set of 2(3x – 1) ≥ 4x – 6?
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Now you have
6x - 2 \geqslant 4x - 6

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so you have
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3 years ago
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-1

Step-by-step explanation:

-7/10+7/15+1/-20+-9/10+11/15+11/-20

= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20

= -16/10 + 18/15 + 12/-20

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= (-8+6-3)/5

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goldenfox [79]

Answer: b) The probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

Step-by-step explanation:

Given that:

Number of samples = 100

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Proportion =number defective samples / total samples

P = 15 / 100 = 0.15

Hence, the probability that an item produces is defective is 0.15.

However, due to sampling Variations, the probability will be corrected for these variations. Hence, probability that an item produced by this process is defective is likely to be close to 0.15, but not exactly equal to 0.15.

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3 years ago
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