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galben [10]
2 years ago
11

Coulddd i be helped really quick?

Mathematics
2 answers:
jolli1 [7]2 years ago
7 0
  • Cover charge be x
  • Customers be y

So

For every increase in cover price of x means 5x+0.5 decreases customers by 30

So

the expression is

  • 5x+0.5=300y-30
  • 5x=300y-30.5
  • 300y=5x-30.5
  • 5x-300y-30.5=0
yuradex [85]2 years ago
3 0
Answer for 4 is 56 costumers
Answer for 30 is x+56=y-$5.05
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The length of the rectangle is 4cm less than its width . what are the dimensions of the rectangle if its area is 140
melomori [17]
Let the width of the rectangle be x
Then length =x-4
Area=x(x-4)=140
x²-4x=140
x²-4x-140=0
x²-14x+10x-140=0
x(x-14)+10(x-14)=0
(x-14)(x+10)=0
Therefore,length=14 cm and  width=10 cm

8 0
3 years ago
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Paha777 [63]

Answer:im lonely

Step-by-step explanation:

6 0
3 years ago
In the solution of the equation 5 + 3x = -2x + 9, 2x is added to the equation first. Which of the following should be done next?
Ivanshal [37]
3x + 2x = 9 - 5
5x = 4 
x = 0.8
7 0
3 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
Four expressions are shown:
Oksana_A [137]
The answer is 12x+4 and 2(6x+2)

Hope it helps.
7 0
3 years ago
Read 2 more answers
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