Relflect the shape in the mirror line

Mathematics

1 answer:

Ronch [10]2 years ago

7 0

Answer:

its hard to do this without a graph to draw on for you but see explanation

Step-by-step explanation:

from each point count how many units it is from the mirror line and then count that many in the opposite direction. for example, the top left point is 3 away from the mirror line from the left so count 3 units to the right of the mirror line and that is where that point will be.

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Which part of the graph best represents the solution set to the system of inequalities y<_ x+1 and y+x<_ -1

Pavel [41]

Hello!

Remember that the symbols: ≤ and ≥ are graphed as a solid line. While the symbols: < and > are graphed as a dotted line.

Also, before graphing, it would be better to convert both equations to slope-intercept form.

y ≤ x + 1 is already in slope-intercept form.

y + x ≤ -1 is not written in slope-intercept form. (Slope-intercept form: y = mx + b)

y + x ≤ - 1 (subtract x from both sides)

y ≤ -x - 1

Graphing those lines, you get the graph below. You can see that Part C best represents the solution set systems of inequalities, because that is where both of the shaded lines intersect.

Answer: Part C