P(x) = (x^2)(x - 4)^2(x + 4) + some constant(b)
2025 = (1^2)(1 - 4)^2(1 + 4) + b
2025 = 45 + b
b = 1980
Complete Equation:
p(x) = (x^2)(x - 4)^2(x +4) + 1980
or expanded form
p(x) = x^5 - 4x^4 - 16x^3 + 64x^2 + 1980
Answer:
we can not reject any value
Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval
If we established CI = 95 % then α = 5 % and α/2 = 0,025
From data we find the mean of the values
μ₀ = 12,03 and σ = 0,07
From z table we find z score for 0,025 is z(c) = ± 1,96
So limits of our CI are:
12,03 + 1,96 = 13,99
12,03 - 1,96 = 10,07
And all our values are within ( 10,07 , 13,99)
So we can not reject any value
Answer:
-24
Step-by-step explanation:
Easy way: 42 - 18 = 24, then translate it to negative 24 because your numbers are negative.
A little bit harder way: -42 + (-18) or -42 + 18 = -24
Im a little confused here because there isn't enough information to go on or I might be reading it wrong.
Step-by-step explanation:
I am going to guest 25 mins
