Since 40%=40/100=4/10, we can divide 11 by 10 and multiply that by 4 to get the weight gained, which is 1.1*4=4.4. The weight gained paired with the starting weight = 10+4.4=14.4
Assuming that the center of each circle is at point C and D, then both have a radius of 7cm. We know that the formula for solving area of the circle is A=pi*r².
Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
C1 area=3.1416*7²
C1 area=153.9384 cm²
Summation of the area of circle C and D is shown below:
Sum area=2*153.9384
Sum area=307.8768cm²
The answer is 98pi.
Answer:
28
Step-by-step explanation:
Since, Sum of triangle is equal to 180°
180 = 2x + 50 + 3x - 10
180 = 5x + 40
180 - 40 = 5x
140 = 5x
140/5 = x
28 = x
Step-by-step explanation:
radius of sphere, rs
radius of cylinder, rc
height of cylinder, h
given: h = rs = rc =r..eq1
volume of cylinder, vc = 27pi ft...eq2
volume of cylinder, vc = pi × rc^2 × h...eq3
volume of sphere, vs = 4/3(pi×rs^3)...eq4
subst for h & rs from eqn 1 in eqn 3...
vc = pi x r^2 x r= pi x r^3...eqn 5
subst for vc from eqn 2 in eqn 5...
=> 27 pi ft = pi x r^3
=> 27 = r^3
=> r = 3ft...eqn 6
subst for rs from eqn 1 in eqn 4
vs = 4/3 (pi x r^3)...eqn7
subst for pi x r^3 from eqn 5 in eqn 7
vs = 4/3 vc = 4/3 (27pi ft) = 36 pi ft
