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IgorLugansk [536]
3 years ago
9

Set up the integral that would give the volume v generated by rotating the region bounded by the given curves about the y-axis.

y = x^3, y = 0, x = 5

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
Consider, pls, this solution.
Note, that V1 marked with orange lines (see the graph), V2 - with green colour.

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Can somebody write this is quadratic form please
galina1969 [7]

To write an equation in standard form, move each term to the left side of the equation and simplify.

ax2+bx+c = 0ax2+bx+c = 0

Move all the expressions to the left side of the equation.

−17−8x2−4x+3x2 = 0-17-8x2-4x+3x2 = 0

Add −8x2-8x2 and 3x23x2.

−17−5x2−4x = 0-17-5x2-4x = 0

Reorder the polynomial.

5x2+4x+17 = 0

Step-by-step explanation:

I hope this helped-

7 0
3 years ago
P(x)=(x-2)(x-4)(x-5)
Cerrena [4.2K]

The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

So, we have:

<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

Constant = -2 \times -4 \times -5

Constant = -40

Hence, the constant is -40

<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>

Constant = -2 \times -4 \times 5

Constant = 40

Hence, the constant is 40

<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>

Constant = \frac 12 \times -2 \times -4 \times 5

Constant = 20

Hence, the constant is 20

<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

Constant = 5 \times -2 \times -4 \times 5

Constant = 200

Hence, the constant is 200

<u>P(x) =-5(x-2)(x-4)(x+5)</u>

Constant = -5 \times -2 \times -4 \times 5

Constant = -200

Hence, the constant is -200

Read more about polynomials at:

brainly.com/question/2833285

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2 years ago
A boat is 75 miles west and 60 miles north from the nearest port. What bearing should be taken to sail directly to port? S 39° E
Nimfa-mama [501]
I dont know this is really hard

7 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
lapo4ka [179]
Well...   the segment FG = 4x + 3, the segment GH = 7x - 12, now, the
 
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.

thus, FG = GH
or

\bf 4x+3=7x-12\implies 3+12=7x-4x\implies 15=3x&#10;\\\\\\&#10;\cfrac{15}{3}=x\implies \boxed{5=x}\\\\&#10;-------------------------------\\\\&#10;thus\qquad &#10;\begin{cases}&#10;\overline{FG}=4x+3\\&#10;4(5)+3\\&#10;23\\&#10;------\\&#10;\overline{GH}=7x-12\\&#10;7(5)-12\\&#10;23&#10;\end{cases}\impliedby equal\ halves&#10;\\\\\\&#10;\overline{FH}=23+23\implies \overline{FH}=46\implies 6y-2=46&#10;\\\\\\&#10;6y=46+2\implies y=\cfrac{48}{6}

and fairly sure, you know how much that is.
7 0
3 years ago
(3x+4)^2=14 what are the solutions?
kherson [118]
\bf (3x+4)^2=14\implies \sqrt{(3x+4)^2}=\pm\sqrt{14}\implies 3x+4=\pm\sqrt{14}&#10;\\\\\\&#10;3x=\pm \sqrt{14}-4\implies x=\cfrac{\pm \sqrt{14}-4}{3}\implies x=&#10;\begin{cases}&#10;\cfrac{\sqrt{14}-4}{3}\\\\&#10;\cfrac{- \sqrt{14}-4}{3}&#10;\end{cases}
7 0
3 years ago
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