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IgorLugansk [536]
3 years ago
9

Set up the integral that would give the volume v generated by rotating the region bounded by the given curves about the y-axis.

y = x^3, y = 0, x = 5

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
Consider, pls, this solution.
Note, that V1 marked with orange lines (see the graph), V2 - with green colour.

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1. simplify the expression 10^0
zhuklara [117]
Number 1 is B, number 2 is C and number 3 is A
7 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL UPVOTE!
bagirrra123 [75]
Just "plug n chug" as my teacher would say. In other words, replace the letters with the values. 

Choice A is (7,19) which means x = 7 and y = 19. Let's replace the x and y value with these numbers in both equations. If we get a true equation, then we found the answer. 

2x-y = -5
2*7-19 = -5
14-19 = -5
-5 = -5 ... true
So that works. Let's try the other equation
x+3y = 22
7+3*19 = 22
7+57 = 22
64 = 22 ... false 
So choice A is NOT the answer because of this. Let's try out choice B
2x-y = -5
2*4-9 = -5
-1 = -5 ... false
so B doesn't work either. How about C? 
2x-y = -5
2*8-21 = -5
-5 = -5 ... that works
x+3y = 22
8+3*21 = 22
71 = 22 ... but this is false
So D has to be the answer. Let's check to confirm or not
2x-y = -5
2*1-7 = -5
-5 = -5 ... true
x+3y = 22
1+3*7 = 22
22 = 22 ... true
BOTH equations are true at the same time so (1,7) is definitely the final answer


6 0
3 years ago
I need to know how to get the answer and what the answer is
Vedmedyk [2.9K]
(Can't really explain it... hopefully these steps can help you.. maybe I'm just too lazy..)

2h^3j^-3k^4
-----------------
3jk

2h^3k^4
= -------------
3j^4k


2h^3k^3
= --------------
3j^4
8 0
3 years ago
What is the gradient of the line (-4, 10) to (-2, 6)<br>​
Andre45 [30]

Answer:

(2,-4)

Step-by-step explanation:

-4+2=-2

10+-4=10-4=6

6 0
2 years ago
You Try:<br> True or False: (-8) + 9 = 9+ (-8)<br> Show your work to prove your answer.
poizon [28]

Answer:

true

Step-by-step explanation:

(-8) + 9=1

9+(-8)=9-8=1

4 0
3 years ago
Read 2 more answers
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