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just olya [345]
3 years ago
13

How do you factor this equation? 2k2+9k+9

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

2k^2+9k+9

(2k+3)(k+3)


I hope that's help !

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If f(x) = 3^2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
timurjin [86]

Answer:

(f - g)(2) = 11

Step-by-step explanation:

f(x) = 3² + 1

g(x) = 1 - x

(f - g)(2) = f(2) - g(2)

f(2) = 9 + 1 = 10

g(2) = 1 - 2 = -1

10 - (-1) = 10 + 1 = 11

(f - g)(2) = 11

4 0
3 years ago
(Apex!) Select the two values of x that are roots of this equation 3x-5=-2x^2
katovenus [111]

Answer:

B and D

Step-by-step explanation:

Write as a quadratic

-2x² - 3x + 5 = 0

Factor

-2x² - 5x + 2x + 5 = 0

-x(2x + 5) + 1(2x + 5) = 0

(1 - x)(2x + 5) = 0

To make the equation 0, x is either 1 or -5/2.

4 0
3 years ago
Help me, please :)<br> I need to find the value of x
irina1246 [14]
The vale of x is 55 !!
3 0
3 years ago
In the following table of values, the first differences are
ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

d = y_{n+1} - y_n

So, we have:

d = y_2 - y_1 = 27 - 34 = -7

d = y_3 - y_2 = 20 - 27 = -7

d = y_4 - y_3 = 13 - 20 = -7

d = y_5 - y_4 = 6-13 = -7

<em>Hence, the first differences are -7 (all through)</em>

5 0
3 years ago
The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou
Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2  surgeries  in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as\sigma^2 = mean = 6.2

hence, standard deviation is given as \sqrt{6.2} = 2.48998

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2  surgeries  in a given day is

P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)

                 = \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}

                 = 0.002029 + 0.012582+ 0.039006

                 = 0.053617

                = 0.0536

7 0
3 years ago
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