a students body temperature is 98. 6 degrees Fahrenheit. what is the temperature on the Celsius scale

agasfer [191]

Answer:

Point A and point B have 11 units between

Step-by-step explanation:

If the distance between 0 and 10 is 10 also known as the absolute value, you just add one more unit because it starts at -1

So 10 + 1 = 11 and because we are using 10 is greater than 1 its positive so the answer is 11

Hope this helps :)

8 0

2 years ago

The perimeter of a triangle is 38cm. The first side is 10cm longer than the second side, the third side is twice as long as the

Natalija [7]

Side 1: 17 Cm.
Side 2: 7 Cm.
Side 3: 14 Cm.

Hope This Helped.

8 0

2 years ago

Help please! make sure to tell me the answer and an explanation!

soldier1979 [14.2K]

Answer: 10

Step-by-step explanation:

So since this is all about perimeter you just got to add the values together. So lets use 12 as the denominator for every fraction. 1/4 is equal to 3/12 and 2/3 is equal to 8/12. So in conclusion 3/12 plus 8/12 and 1/12 will equal 1 in total. and then add up all the whole numbers 4 + 2 + 3 + 1 will get you 10. So 10 is your answer.

Please make me brainliest

8 0

2 years ago

Bailey bought a lawnmower for $600. The value of the lawnmower depreciates 2% every year. What is the value of the lawnmower aft

givi [52]

Answer:

$542

Step-by-step explanation:

we know that

The equation of a exponential decay function is given by

$y=a(1-r)^x$

where

y is the value of the lawnmower

x is the time in years

a is the initial value

r is the rate of change

we have

$a=\$600\\r=2\%=2/100=0.02$

substitute

$y=600(1-0.02)^x$

$y=600(0.98)^x$

For x=5 years

$y=600(0.98)^5=\$542$

8 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let X = number of students who read above the eighth grade level.

(a)

A sample of n = 269 students are selected. Of these 269 students, X = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

$\hat p=\frac{X}{n}=\frac{224}{269}=0.8327$

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

$1-\hat p=1-0.8327$

$=0.1673$

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

n = 709

X = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

$\hat q=1-\hat p$

$=1-\frac{X}{n}$

$=1-\frac{546}{709}$

$=0.2299\\\approx 0.229$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)$

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0

3 years ago