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skelet666 [1.2K]
4 years ago
8

I need some help please

Mathematics
1 answer:
dimulka [17.4K]4 years ago
4 0
I think the answer is the third one, but idk.
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HELP I WILL GIVE BRAINLY THING ​
lana [24]

Answer:

The answer is A.

Step-by-step explanation:

Hope this helps.

4 0
3 years ago
What is the product? (x-5)(2x+3x-1)
Firlakuza [10]
I assume the first term of the trinomial is 2x^2, and you left out the exponent.

Multiply each term of the binomial by each term of the trinomial.
Then collect like terms.

(x - 5)(2x^2 + 3x - 1) =

= x * 2x^2 + x * 3x + x * (-1) - 5 * 2x^2 - 5 * 3x - 5 * (-1)

= 2x^3 + 3x^2 - x - 10x^2 - 15x + 5

= 2x^3 - 7x^2 - 16x + 5






5 0
3 years ago
Read 2 more answers
5 divied by 5/6 please let me know
yaroslaw [1]
5 / (5/6)...when dividing with fractions, flip what u r dividing by, then multiply

5 * 6/5 =
30/5 =
6 <==
7 0
3 years ago
Read 2 more answers
Can someone help me with this please
Pepsi [2]

Answer:

H' = (-4,-4)

I' = (-2,-4)

J' = (-2,-5)

6 0
3 years ago
The equation for the circle is:
noname [10]
(-8,12)

the equation for a circle, centered at (h,k) with radius r is
(x-h)^2+(y-k)^2=r^2

so you need to get your equation in this form. completing the square is one way to do this. separating x and y terms you get
x^2+16x+y^2-24y+159=0
which can then be rewritten using complete the square
x^2+16x+64+y^2-24y+144+159=0+64+144
which is equivalent to
(x+8)^2+(y-12)^2+159=208 \\ (x+8)^2+(y-12)^2=49

so your center is the point (-8,12) and the radius would be 7.

8 0
3 years ago
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