V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
Answer:
Answer: 3 1/2 and -10 1/2 are the two numbers.
Step-by-step explanation:
Let x and y be the two unknown numbers.
x+y=-7 [Given]
x-y=14 [Given]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x+y=-7 [Given]
(y+14)+y=-7 [Subtitution]
2y+14=-7 [Combine like terms]
2y=-21 [Subtract 14 from both sides]
y=-21/2 [Divide both sides by 2]
y=-10 1/2 [Division]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x=-10 1/2 + 14 [Substitution]
x= 3 1/2 [Addition]
Check:
x+y=-7 [Given]
3 1/2 + -10 1/2?=-7 [Substition]
-7=-7 [Addition]
QED
x-y=14 [Given]
3 1/2 - -10 1/2?=14 [Substitution]
3 1/2 + 10 1/2?=14 [Change the sign of the subtrahend and add]
14=14 [Addition]
QED
Answer: 3 1/2 and -10 1/2 are the two numbers.
Answer:
Refer the attachment for the answer
Hope it helps
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Kilo = 1,000
Hecto = 100
Deca = 10
Base (unit) = 1
Deci = 0.1
Centi = 0.01
Milli = 0.001
