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kkurt [141]
3 years ago
6

Name similarities between innovation and invention

Computers and Technology
1 answer:
Gekata [30.6K]3 years ago
4 0
Similarities:
-Innovation and invention are both new things/changes that make something new
-Innovations, as well as an inventions, are both things that are created to better peoples lives.
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Search engines enable you to:A. talk to people via the computer.B. locate Web pages related to a specific subject.C. connect to
GalinKa [24]
The correct answer is B. locate Web pages related to a specific subject.

An example of a search engine is Google: it helps you find Websites with the content you're looking for.
3 0
3 years ago
Which form of media allows the audience to share in and comment on the content immediatly
Luba_88 [7]

twitter

they will allow you to share comments about any topic you want

4 0
3 years ago
A form of brainstorming that serves as a visual aid to thinking laterally, helps explore a problem (usually by stating the probl
ELEN [110]

Answer:

The answer is BRAINSTORMING

Explanation:

<em>A visual aid to thinking laterally and exploring a problem, usually by stating the problem in the center  of the page and radiating outward spokes for components of the problem. Each component can then be considered separately with its own spokes, so that each point , thought, or comment is recorded.</em>

7 0
3 years ago
Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th
Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = [\frac{DG-IP}{M-IP} ]

Insert values in the formula = [\frac{2400-20}{700-20} ]

Then,        = [\frac{2380}{680} ] = [3.5]

The generated numbers of the fragment is 4

  • If FV = 1 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=0 and F=1.
  • If FV = 2 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=85(85*8=680 bytes) and F=1.
  • If FV = 3 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=170(170*8=1360 bytes) and F=1.
  • If FV = 4 then, bytes in data field of DG= 2380-3(680) = 340 and id=422 and FO=255(255*8=2040 bytes) and F=0.

3 0
3 years ago
5-11) (Find the Smallest Value) Write an application that finds the smallest of several integers. Write a program which first as
Elanso [62]

Answer:

import java.util.Arrays;

import java.util.Scanner;

public class num4 {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

       System.out.println("How many numbers? ");

       int n = in.nextInt();

       int []intArray = new int[n];

       //Entering the values

       for(int i=0; i<intArray.length;i++){

           System.out.println("Enter the numbers");

           intArray[i]=in.nextInt();

       }

       System.out.println(Arrays.toString(intArray));

       int min =intArray[0];

       for(int i =0; i<intArray.length; i++){

           if(min>intArray[i]){

               min = intArray[i];

           }

       }

       System.out.println("The Minimum of the numbers is "+min);

   }

}

Explanation:

  • Using Java programming language
  • Prompt the user for the number of values
  • Using Scanner class receive and store in a variable
  • Create an array of size n
  • Using an for loop continuously ask the user to enter the integers
  • Print the array of integers
  • Using another for loop with an if statement, find the smallest element in the array of numbers
  • Output the the smallest number
8 0
3 years ago
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