Answer:
Following are the answer to this question:
Step-by-step explanation:
Given:
n = 30 is the sample size.
The mean
= 7.3 days.
The standard deviation = 6.2 days.
df = n-1

The importance level is
= 0.10
The table value is calculated with a function excel 2010:

The method for calculating the trust interval of 90 percent for the true population means is:
Formula:


It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.
3.7491739193721... because rational numbers are numbers like -3 -2 -1 0 1 2 3 and decimals like 3.3333333 and 1.62162162162162 because they repeat the same numbers like a pattern, with 3 repeating or 162.The decimal 3.7491739193721... is not rational, or irrational because it is not repeating or terminating, or stopped.
Answer:
hsuvsjvBcsjfbdkchdkksfsnadeolataogzfdkgcjb
Answer:

Step-by-step explanation:
Component form of a vector is given by
, where
represents change in x-value and
represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector
, the magnitude is
.
190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being
, one leg being
, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.
In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.
Therefore, we have:

To find the other leg,
, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

Verify that
Therefore, the component form of this vector is 
Answer:
x + 29 = 41
Step-by-step explanation:
Trevon received some money, but we don't know how much, so we will represent that with x.
The money he received will be add the amount he had last friday, $29.
The equation will equal his current amount, $41.