Given:
The side of square = 12 in.
Scale factor of enlargement = 3 in : 2 m
To find:
The proportion that is use to solve the side length, x, of the enlarged square.
Solution:
Let, the side of length of enlarged square = x m
In case of enlargement the corresponding sides are proportional.
Divide both sides by 3.
Therefore, the required proportion is and the side length of the square after enlargement is 8 m.
Answer:
3+(6-2)*4=19
Step-by-step explanation:
Due to PEMDAS, it would first be required to do "6-2", which is 4.
Then, the 4 in the parenthesis is multiplied by the 4 on the outside, making 16.
Finally, 3 would be added to 16, making 19.
A is the correct answer
Or
Vertex = (-5,-4), y-intercept = (0,21), x-intercepts = (-7,0) and (-3,0), axis of
symmetry is x = -5
One of the zeroes would be : x = 1
f (1) = 1^3 + 6(1) ^2 + 3 (1) - 10
f(1) = 1 + 6 + 3 - 10
f (1) = 10 - 10
f (1) = 0
Hope this helps
You should get a hoodie. Thx for free points lol
